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Sunday, 1 April 2012

Oxidation state


element
usual oxidation state

Group 1 metals
always +1

Group 2 metals
always +2

Oxygen
usually -2

Hydrogen
usually +1

Fluorine
always -1

Chlorine
usually -1

Solids


Q. 1.  (a)       If the radius of the Br ion is 0.182 nm, how large a cation can fit in each of the tetrahedral hole.
            (b)       AgI crystallizes in a cubic closed packed ZnS structure. What fraction of tetrahedral site is occupied by Ag ion ?
            (c)       At what temp. range, most of the metals becomes super conductors ?
Ans.    (a)       For a tetrahedron the limiting ratio is 0.225 – 0.414
                        For largest cation highest value 0.414 would be considered.
                        r+ / r = 0.414
                        r+ = 0.414 × 0.182 = 0.075 nm.
            (b)       In FCC there are 8 tetrahedral voids. Out of this ½ is occupied by Ag cation.
            (c)        2 k – 5 k.

Elements


Phosphorus
Phosphorus contains P4 molecules. To melt phosphorus you don't have to break any covalent bonds - just the much weaker van der Waals forces between the molecules.
Sulphur
Sulphur consists of S8 rings of atoms. The molecules are bigger than phosphorus molecules, and so the van der Waals attractions will be stronger, leading to a higher melting and boiling point.
Chlorine
Chlorine, Cl2, is a much smaller molecule with comparatively weak van der Waals attractions, and so chlorine will have a lower melting and boiling point than sulphur or phosphorus.
Argon
Argon molecules are just single argon atoms, Ar. The scope for van der Waals attractions between these is very limited and so the melting and boiling points of argon are lower again.